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(C)=0.2C^2-128C+28.543
We move all terms to the left:
(C)-(0.2C^2-128C+28.543)=0
We get rid of parentheses
-0.2C^2+C+128C-28.543=0
We add all the numbers together, and all the variables
-0.2C^2+129C-28.543=0
a = -0.2; b = 129; c = -28.543;
Δ = b2-4ac
Δ = 1292-4·(-0.2)·(-28.543)
Δ = 16618.1656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(129)-\sqrt{16618.1656}}{2*-0.2}=\frac{-129-\sqrt{16618.1656}}{-0.4} $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(129)+\sqrt{16618.1656}}{2*-0.2}=\frac{-129+\sqrt{16618.1656}}{-0.4} $
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